3(2c+d)-4(c-d)+d^2=

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Solution for 3(2c+d)-4(c-d)+d^2= equation: 


Simplifying
3(2c + d) + -4(c + -1d) + d2 = 0
(2c * 3 + d * 3) + -4(c + -1d) + d2 = 0
(6c + 3d) + -4(c + -1d) + d2 = 0
6c + 3d + (c * -4 + -1d * -4) + d2 = 0
6c + 3d + (-4c + 4d) + d2 = 0

Reorder the terms:
6c + -4c + 3d + 4d + d2 = 0

Combine like terms: 6c + -4c = 2c
2c + 3d + 4d + d2 = 0

Combine like terms: 3d + 4d = 7d
2c + 7d + d2 = 0

Solving
2c + 7d + d2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7d' to each side of the equation.
2c + 7d + -7d + d2 = 0 + -7d

Combine like terms: 7d + -7d = 0
2c + 0 + d2 = 0 + -7d
2c + d2 = 0 + -7d
Remove the zero:
2c + d2 = -7d

Add '-1d2' to each side of the equation.
2c + d2 + -1d2 = -7d + -1d2

Combine like terms: d2 + -1d2 = 0
2c + 0 = -7d + -1d2
2c = -7d + -1d2

Divide each side by '2'.
c = -3.5d + -0.5d2

Simplifying
c = -3.5d + -0.5d2

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